Honor V10 spotted at TENAA with 5.99-inch 18:9 Display, Kirin 970 SoC

A new smartphone from Huawei’s sub-brand Honor dubbed as V10 has received the certification from TENAA, the Chinese regulatory authority with a code name BND-AL00 which revealed most of its specifications.

 

According to the TENAA listing:-

Honor V10 will feature a 5.99-inch FullHD+ 18: 9 Display with a resolution of 2160×1080 pixels. The device will be powered by Kirin 970 processor. It will run on Android 8.0 Oreo with EMUI 8.0.

In the camera sections, the smartphone offers Honor V10 will have 16MP+20MP dual camera setup with LED Flash while on the front it will have a 13MP snapper. It comes with 6GB of RAM and 64GB or 128GB of onboard storage.

Honor V10 will be announced in China on November 28th and it is expected that the price of the device will be around 2999 yuan ($451.98).

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